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Sed

Greedy Regexp in sed

http://www.skybert.net/unix/non-greedy-matching-in-sed/

What you need to do, is to match against everything but the closing delimiter, in our case, the '@'. This is done with the character group notation and the negator ^ in front of the closing delimiter:

echo 'The @HashMap@ and @ArrayList@ classes are great!' | sed 's|@\([^@]*\)@|<code>\1</code>|g'

Multiple sed cmds in cli

sed "s/:/\//g; s/git@/https:\/\//"

Change date format

sed -i -E "s|([0-9]{4})/([0-9]{2})/([0-9]{2})|\1-\2-\3|" transactions-*

Remove empty lines and comments

https://stackoverflow.com/a/23808815

sed -e '/^\s*#.*$/d' -e '/^\s*$/d' inputFile

Replace after matching line

https://stackoverflow.com/a/18620241

i.e. Replace third line after match (foo):

sed -i '/foo/{n;n;n;s/bar/baz/}' test.txt